PV Gap

Lynn Said:

Calculating Energy produced via solar panels?

We Answered:

well, I had the same question a while back and found great information like this :

Individual solar modules that are measured in watts have a particular voltage (around 40 volts) and a particular amperage (around 5 amps). A solar module with 40 volts and 5 amps is called a 200-watt module, which means that it has the potential to produce 200 watts of electricity when in direct sunlight.

Also, you will need to determine the load of your appliances, there is a great calculator on the website shown below

Dorothy Said:

I am really struggling with A2 Physics question?

We Answered:

This has nothing to do with nuclear physics.

your units are confused. I think the input power is 1.4kW/m², that is one reason you have problems, incorrect units.

1.4kW/m² x 2.5 m² = 3.5 kW or 3500 watts

electrical power out is P = E*I = 20v x 2.4 amps = 48 watts

Efficiency is Pout/Pin = 48/3500 = 0.0137 or 1.37%

.

Alfredo Said:

Efficiency of electricity - please help me out! I'll show you my working out.?

We Answered:

I cannot make out wat u hav done, clearly. I will do my best in giving my solution. U urself check out where u went wrong.
b)
400 J reaches earth surface to panel per sec [okay]
For travelling 10 metres, the energy required is 350 J.
Since the time taken is 25 s,
Power = 350/25 = 14 J/s.
Overall efficiency of panel and motor
= power given out / power absorbed
= 14/400 = .035 = 3.5%

For (a),
Power of car = 14 J/s (see previous section)
140 J is converted into electrical energy per second.

Hence, Efficiency of panel
= 14/140 = 0.1 or 10%